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4w^2-25w+36=0
a = 4; b = -25; c = +36;
Δ = b2-4ac
Δ = -252-4·4·36
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-7}{2*4}=\frac{18}{8} =2+1/4 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+7}{2*4}=\frac{32}{8} =4 $
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